Learn about Senior Chemistry, Equilibrium 6, in this comprehensive video by bannanaiscool.
Read the full transcript »

Male Speaker: So in previous examples we've been saying that all we have no concentration on the certain product and so we know that we have to lose from this side and lose excess on this side to gain over here, you know in this case, if you have zero here even If you had a concentration here we have to loose from this side to gain something here, which you know what if we have a concentration of well let's says its one moles per liter and lets say you have a concentration of everything. So which way does this reaction have to go, shift in order to equilibrium, is it an equilibrium, everything is equal no, no, no, look if you put all these into expressions and this cause one, one, one can you all understand that the expression would be one times one before one time well which it goes one. So by plugging those numbers into an expression, before they are actually and equilibrium concentration, but still an additional concentration. You are not finding K you are just finding a quotient called Q, and if the Q value is less than K, now here we said that value by plugging these into the expression would be number one, but the K value is as now we want be at equilibrium at 5.10, so that means then you need to make more products and have less reactants to make that number go up to 5.1, which of courses is a Q, was the number one. So when Q is less than K, the reaction shifts to the right, to make more of these you put the pluses on this side and minuses on this side, but what happens if your Q value greater than K, then you got too much product and not enough reactant and so that the reaction shifts to the left and it loose from the product side to gain on the reactant side, what if Q equaled K, right then you are at equilibrium.

Advertisement
Advertisement
Advertisement